BUYING2 SWEET

I just started looking at the problem BUYING SWEET my hunch tells me that correct condition/logic to solve the above problem is this ...

(sum % total_sweet) if find any note else then remainder then the customer is not an adequate customer. Work properly on the all the Test case found

Test case 1

4 7
10 4 8 5

Answer

[10,4,8 ,5].sum
## sum is 27
rem = 27 % 7  6
##rem = 6
i = 0;
adequate = true
for i < a.length:
     if a[i] < 6
        adequate = false
        break

Customer is not adequate

Test Case 2

1 10
12

Answer

   [12].sum
   rem = 12%10
   ## rem is 2
   No number less them 2 hence customer is adequate.

Test Case 3

2 10
20 50

Answer

[20, 50].sum
## 70
rem = 70 % 10
## 0
No number less then 0

Customer is adequate.

But with Limited Test case I'm not sure if the above logic is correct can some please provide some more TEST case so that I can verify them.

EDITED: I just wrote the initial implementation Getting WRONG ANSWER but the editorial https://discuss.codechef.com/questions/3250/buying2-editorial matched with my belief.

Here the Code I submitted https://www.codechef.com/viewsolution/15221523